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Q.

A rubber cord catapult has cross sectional area 25mm2 Initial length of rubber cord is 10 cm  It is stretched by 5 cm and then released to project a stone of mass 5g. Taking the young’s modulus for rubber to be 5 × 108N/m2 Then the velocity of the stone is.

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a

20 m/s

b

100 m/s

c

150 m/s

d

250 m/s

answer is D.

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Detailed Solution

From conservation of energy 12mv2=12Ystrain2volume5×10-3v2=5×108×510 2×25×10-6×10×10-2v2=25×1044    ; v=250
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