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A running man has half the kinetic energy that a body half his mass has. The man speeds up by f m/s and then has the same kinetic energy as the boy. The original speed of the man is

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a

(1+2)m/s

b

(2+2)m/s

c

(3+2)m/s

d

2m/s

answer is A.

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Detailed Solution

Given that E1=E2/2 or 12mv12=1212×m2×v22 or v2=2v1 Finally ,12mv1+12=12×m2×v22 =12×m2×2v12 V1=(2+1)m/s

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