A running man has half the kinetic energy of that of a boy of half of his mass. The man speeds up by 1m/s so as to have same K.E. as that of the boy. The original speed of the man will be
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a
2 m/s
b
(2−1) m/s
c
1(2−1)m/s
d
12m/s
answer is C.
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Detailed Solution
Let m = mass of boy, M = mass of manv = velocity of boy, V = velocity of man12MV2=1212mv2 …..(i)12M(V+1)2=112mv2 …..(ii)Putting m=M2 and solving V=12−1
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A running man has half the kinetic energy of that of a boy of half of his mass. The man speeds up by 1m/s so as to have same K.E. as that of the boy. The original speed of the man will be