Q.

A running man has half the kinetic energy of that of a boy of half of his mass. The man speeds up by 1m/s so as to have same K.E. as that of the boy. The original speed of the man will be

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a

2 m/s

b

(2−1) m/s

c

1(2−1)m/s

d

12m/s

answer is C.

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Detailed Solution

Let m = mass of boy, M = mass of manv = velocity of boy, V = velocity of man12MV2=1212mv2      …..(i)12M(V+1)2=112mv2 …..(ii)Putting  m=M2 and solving  V=12−1
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A running man has half the kinetic energy of that of a boy of half of his mass. The man speeds up by 1m/s so as to have same K.E. as that of the boy. The original speed of the man will be