A running man has half the kinetic energy that a running boy of half his mass has. The man speeds up by 1.0 m/s and now has the same kinetic energy as the boy. The original speed of the man expressed in m/s units must be
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a
2+1
b
2-1
c
2+2
d
2-2
answer is A.
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Detailed Solution
K.E of man = 12(K.E of boy)12mv2=1212m2v12-------(1)Also given, 12mv+12=12m2v12------2Divide (1) with (2) to get v