Q.

S1  and  S2 are two hollow concentric spheres with charge q and 2q. Space between  S1  and  S2 is filled with a dielectric of dielectric constant K =5. The ratio of flux through S2 and flux through  S1 is K'.  Then find the value of   9K' 11.

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

answer is 9.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

With air in the space, between  S1 and  S2.  ϕS1=qε0  and  ϕS2=2qε0When a medium of K = 5 is filled in space ϕ S1'=QKε0=ϕS15=q5ε0And in this case, flux through S2 ϕ S2'=flux  of  S1+flux  of  charge  2q=q5ε0+2qε0=q+10q5ε0=11q5ε0So, ratio ϕS1'ϕS2'=11=K'So, 9K'11=9
Watch 3-min video & get full concept clarity
Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
How to Join IIT after 10th
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
How to Join IIT after 10th
whats app icon
S1  and  S2 are two hollow concentric spheres with charge q and 2q. Space between  S1  and  S2 is filled with a dielectric of dielectric constant K =5. The ratio of flux through S2 and flux through  S1 is K'.  Then find the value of   9K' 11.