S is a solid neutral conducting sphere. A point charge q of I x 10-6 C is placed at point A ,C is the center of sphere, and AB is a tangent. BC = 3 m and AB = 4 m.

Distance AC is given by, AC = 5 mPotential at due to charge q at A is given byV=kqAC=9×109×1×10−65=1.8×103=1.8kVPotential at B is given byVB=VBdue to q+VBinduced VBi= Potential at B due to induced charge Thus 1.8×103=kqAB+VBi=2.25×103+VBiVBi=−0.45kVSo (1) and (3) are correct.