A sample of 0.1 g of water at 1000C and normal pressure1.013×105 N m-2 requires 54 Cal of heat energy to convert to steam at1000C. If the volume of the steam produced is 167.1 cc the change in internal energy of the sample, is

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104.3 J

208.7 J

42.2 J

84.5 J

answer is B.

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Detailed Solution

Using first law of thermodynamics,ΔQ=ΔU+ΔW⇒54×4.18=ΔU+1.013×105167.1×10-6-0⇒ΔU=208.7 J

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