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Q.

A sand bag of mass ‘m’ is suspended from a long string. A bullet of mass m20 moving with a horizontal velocity ‘V’ strikes it and gets embedded into it. Calculate the velocity gained by the bag in this process. Also calculate the fraction of energy lost in this process

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a

V21&2022

b

V19&2021

c

V24&1820

d

V21&2021

answer is D.

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Detailed Solution

Mass of sand bagm1=m Mass of bullet m1=m20horizontal velocity =‘V’from law of conservation of momentumm20V=(m1+m2)V'⇒V'=V21The fraction of energy lostKEi−KEfKEi=m1m1+m2=mm+m20=2021
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