First slide

Motion of planets and satellites

Question

In a satellite if the time of revolution is T, then kinetic energy is proportional to

Moderate

A

$\frac{1}{T}$
B

$\frac{1}{T^{2}}$
C

$\frac{1}{T^{3}}$
D

$T^{- 2 / 3}$

Solution

Time period of a sattelite is T= 2 $π$ $\sqrt{\frac{R^{3}}{G M}}$
Kinetic energy = $\frac{1}{2} m {v_{0}}^{2}$ =m $\frac{2 π^{2} R^{2}}{T^{2}}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App