Questions

A satellite is launched into a circular orbit of radius R around the earth. A second satellite is launched into an orbit of radius (1.01)R. The period of the second satellite is larger than that of the first one by approximately

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0.5%

1.0%

1.5%

3.0%

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detailed solution

Correct option is C

In the problem orbital radius is increased by 1%.Time period of satellite T∝r3/2 Percentage change in time period = 32 (% change in orbital radius) = 32(1%)=1.5%

Similar Questions

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(ii) Period of oscillation of mass inside the tunnel bored along the diameter of the earth $(T_{m a})$
(iii) Period of simple pendulum having a length equal to the earth’s radius in a uniform field of 9.8 N/kg $(T_{s p})$
(iv) Period of an infinite length simple pendulum in the earth’s real gravitational field $(T_{i s})$