Questions

# A satellite is launched into a circular orbit of radius R around the earth. A second satellite is launched into an orbit of radius (1.01)R. The period of the second satellite is larger than that of the first one by approximately

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a
0.5%
b
1.0%
c
1.5%
d
3.0%

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detailed solution

Correct option is C

In the problem orbital radius is increased by 1%.Time period of satellite T∝r3/2  Percentage change in time period = 32 (% change in orbital radius) =  32(1%)=1.5%

Similar Questions

In the following four periods
(i) Time of revolution of a satellite just above the earth’s surface  $\left({T}_{st}\right)$
(ii) Period of oscillation of mass inside the tunnel bored along the diameter of the earth  $\left({T}_{ma}\right)$
(iii) Period of simple pendulum having a length equal to the earth’s radius in a uniform field of 9.8 N/kg  $\left({T}_{sp}\right)$
(iv) Period of an infinite length simple pendulum in the earth’s real gravitational field  $\left({T}_{is}\right)$

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