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A satellite is launched into a circular orbit of radius R around the earth. A second satellite is launched into an orbit of radius (1.01)R. The period of the second satellite is larger than that of the first one by approximately

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a
0.5 %
b
1.0 %
c
1.5 %
d
3.0 %

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detailed solution

Correct option is C

In the problem, the orbital radius is increased by 1%Time period of satellite, T∝r3/2Percentage change in time period=32(% change in orbital radius )=32(1%)=1.5%


Similar Questions

In the following four periods     
(i) Time of revolution of a satellite just above the earth’s surface  (Tst)
(ii) Period of oscillation of mass inside the tunnel bored along the diameter of the earth  (Tma)
(iii) Period of simple pendulum having a length equal to the earth’s radius in a uniform field of 9.8 N/kg  (Tsp)
(iv) Period of an infinite length simple pendulum in the earth’s real gravitational field  (Tis)
 


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