First slide

Keplers 3 Laws

Question

A satellite of mass m is at distance r from the centre of the earth. Another satellite B of mass 2m is at distance 4r from earth’s centre . Their time periods are in the ratio

Easy

A

1:8
B

1:16
C

1:32
D

$1 : 2 \sqrt{2}$

Solution

${[\frac{T_{1}}{T_{2}}]}^{2} = {[\frac{r_{1}}{r_{2}}]}^{3} \Rightarrow \frac{T_{1}}{T_{2}} = {[\frac{r_{1}}{r_{2}}]}^{\frac{3}{2}} = \frac{1}{8}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App