A satellite of mass m is just placed over the surface of earth. In this position mechanical energy of satellite is E1. Now it starts orbiting round the earth in a circular path at height h= radius of earth. In this position, kinetic energy, potential energy and total mechanical energy of satellite are K2, U2 and E2 respectively. Then

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U2=E12

E2=E14

K2=−E2

K2=−U22

answer is A.

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Detailed Solution

E1=−GMmRU2=−GMm2R (r=R+R=2R)K2=GMm4Rand E2=−GMm4R

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