A satellite of mass m is orbiting the earth in a circular orbit. Height of the satellite above the surface of earth is R.Where R = radius of earth. If g be the accelaration due to gravity on the surface of earth, then total energy of the satellite is
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a
-mgR
b
-2mgR
c
-14mgR
d
-12mgR
answer is C.
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Detailed Solution
Total energy E=-GMm2r=-G.M.m2(R+R)=-GMm4R=-m.GMR2.R4⇒E=-14mgR ∵g=GMR2