Questions
A satellite of mass m is orbiting the earth (of radius R ) at a height h from its surface. The total energy of the satellite in
a
mg0R22(R+h)
b
-mg0R22(R+h)
c
2mg0R2R+h
d
-2mg0R2R+h
detailed solution
Correct option is B
Total energy of satellite at height h from the earth surface, E=P.E.+K.E.=-GMm(R+h)+12mv2………..(1) Also, mv2(R+h)=GMm(R+h)2 or, v2=GMR+h…..(2) From eqns. (1) and (2), E=-GMm(R+h)+12GMm(R+h)=-12GMm(R+h)=-12GMR2×mR2(R+h)=-mg0R22(R+h)∵g0=GMR2Talk to our academic expert!
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