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Q.

A satellite of mass m revolving in a circular orbit of radius r around the earth of mass M has a total energy E. Then its angular momentum will be :

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a

Em2r2

b

E2mr2

c

2mEr2

d

2mEr

answer is C.

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Detailed Solution

Velocity of the satellite is GMr, angular momentum  L =mvrL= mGMr r =mGMr----1given total energy -GMm2r= E⇒GM=2ErmNow, substituting the value of GM  in 1L=m2Ermr=2Er2m
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