A satellite of mass m revolving in a circular orbit of radius r around the earth of mass M has a total energy E. Then its angular momentum will be :
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a
Em2r2
b
E2mr2
c
2mEr2
d
2mEr
answer is C.
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Detailed Solution
Velocity of the satellite is GMr, angular momentum L =mvrL= mGMr r =mGMr----1given total energy -GMm2r= E⇒GM=2ErmNow, substituting the value of GM in 1L=m2Ermr=2Er2m