A satellite is moving in a circular orbit of radius 2R around earth (Radius = R) and its total energy is found to be E. If radius of earth shrinks to half of its present radius keeping its mass unchanged, Then potential energy of the satellite when it is on the surface of earth will be
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a
E2
b
4E
c
6E
d
8E
answer is D.
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Detailed Solution
E=-GMm2(2R)=-GMm4RWhen the satellite is placed on the surface of earth (Radius R/2), U=-GMmR/2=2 x 4E=8E