Questions
A satellite is moving in a circular orbit of radius 3R. Where R is the radius of earth. It is slowly losing energy at a constant rate of . Then the time after which its orbital radius will be 2R is (Acceleration due to gravity on the surface of earth is g)
detailed solution
Correct option is D
Ei= Initial total energy =-GMm2 x 3R=-GMm6REf= Final total energy =-GMm2 x 2R=-GMm4R∴t=Ei-Efα=1αGMm4R-GMm6R=GMm12αR=mgR12αTalk to our academic expert!
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