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A satellite is moving in a low nearly circular orbit around the earth. Its radius is roughly equal to that of the earth’s radius Re. By firing rockets attached to it, its speed is instantaneously increased in the direction of its motion so that it become 32  times larger. Due to this the farthest distance from the center of the earth that the satellite reaches is R. Value of R is :

a
4Re
b
2Re
c
25Re
d
3Re

detailed solution

Correct option is D

Ei=-GMm2ReAfter supplying kinetic energy,Ef=-GMm2Re+12 m32GMRe2Ef=-GMm2Re+12 m32GMRe=-GMm4ReLet say a is semimajor axis of new orbit.Ef=-GMm2a   ⇒-GMm4Re=-GMm2a   ⇒2a=4Re We know that major axis can be given as, 2a=rmin+rmax ⇒4Re=Re+rmax  ⇒rmax=3Re

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Similar Questions

Imagine that you are in a spacecraft orbiting around the earth in a circle of radius 7000 km (from the centre of the earth). If you decrease the magnitude of mechanical energy of the spacecraft - earth system by 10% by firing the rockets, then what is the greatest height you can take your spacecraft above the surface of the earth? [Re = 6400 km]


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