Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A satellite is moving with a constant speed’v’ in a circular orbit about the earth. An object of mass’m’ is ejected from the satellite such that it just escapes from the gravitational pull of the earth. At the time of its ejection,the kinetic energy of the object is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

12mv2

b

mv2

c

32mv2

d

2mv2

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

In circular orbit of satellite , potential energy = 2×(kinetic energy)=-2×12 mv2=-mv2∵KE=GmM2r, PE=-GmMrJust to escape from the gravitational pull, its total mechanical energy should be zero. Therefore, its kinetic energy should be +mv2.
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring