A satellite is revolving round the earth with orbital speed V0.If it stops suddenly, the speed with which it will strike the surface of earth would be ( Ve= escape velocity of a particle on earth’s surface)
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a
Ve2V0
b
V0
c
Ve2−V02
d
Ve2−2V02
answer is D.
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Detailed Solution
Just before it strikes the surface of earth12mv2+−GMemR=Ei=−GMemr⇒V2=2GMeR−2GMer=Ve2−2GMeGMe/V02⇒V=Ve2−2V02