First slide

Motion of planets and satellites

Question

A satellite is seen after each 8 hours over equator at a place on the earth when its sense of rotation is opposite to the earth. The time interval after which it can be seen at the same place when the sense of rotation of earth and satellite is same will be

Moderate

A

8 hours
B

12 hours
C

24 hours
D

6 hours

Solution

Given $8 = \frac{2 π}{ω_{1} + ω_{2}} = \frac{2 π}{\frac{2 π}{T_{1}} + \frac{2 π}{T_{2}}}, T_{1} = 24$ hours for earth.
$\Rightarrow T_{2} = 12 hours$ ( $T_{2}$ being the time period of satellite, it will remain same as the distance from the centre of the earth remains constant).
$\Rightarrow T = \frac{2 π}{ω_{2} - ω_{1}} = \frac{2 π}{\frac{2 π}{T_{2}} - \frac{2 π}{T_{1}}} = 24 hours$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App