First slide

Keplers 3 Laws

Question

A satellite is seen after every 6 hours over the equator. It is known that is rotates opposite to that of earth’s direction. Then the angular velocity ( in radians per hour) of the satellite about the centre of earth will b

Moderate

A

$\frac{π}{2}$
B

$\frac{π}{3}$
C

$\frac{π}{4}$
D

$\frac{π}{8}$

Solution

$\begin{array}{l} \frac{2 π}{T_{r e l}} = \frac{2 π}{T_{e a r t h}} + \frac{2 π}{T_{s a t e l l i t e}} \\ \Rightarrow \frac{2 π}{6} = \frac{2 π}{24} + \frac{2 π}{T_{s a t e l l i t e}} \Rightarrow ω_{s a t e l l i t e} = \frac{2 π}{T_{s a t e l l i t e}} = \frac{π}{4} \end{array}$

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