First slide

Thermal expansion

Question

A scale made of material having coefficient of linear expansion $(α_{s})$ at $t_{i} C$ . If temperature is changed to $t_{2} (t_{2} > t_{1})$ then error in measurement of scale is

Easy

A

$Δ L = \frac{L}{α_{S} Δ t}$
B

$Δ L = \frac{1}{L α_{S} Δ t}$
C

$Δ L = L α_{s} Δ t$
D

$L = \frac{Δ L Δ t}{α}$

Solution

$c o e f f i c i e n t o f l i n e a r e x p a n s i o n i s α_{s} = \frac{∆ L}{L ∆ t e m p e r a t u r e} \Rightarrow ∆ L = α_{s} L ∆ t h e r e L i s i n i t i a l l e n g t h o f s c a l e ∆ L i s c h a n g e i n l e n g t h o f s c a l e ∆ t i s c h a n g e i n t e m p e r a t u r e$

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