Questions
The scale of a spring balance reading from 0 to 10 kg is 0.25 m long. A body suspended from the balance oscillates vertically with a period of second. The mass suspended is (neglect the mass of the spring)
detailed solution
Correct option is B
Using F=kx⇒10g=k×0.25⇒k=10g0.25=98×4Now T=2πmk⇒m=T24π2k⇒m=π2100×14π2×98×4=0.98 kgTalk to our academic expert!
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An ideal spring with spring-constant K is hung from the ceiling and a block of mass M is attached to its lower end. The mass is released with the spring initially unstretched. Then the maximum extension in the spring is
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