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Q.

The scale of a spring balance reading from 0 to 10 kg is 0.25 m long. A body suspended from the balance oscillates vertically with a period of  π​/​10 second. The mass suspended is (neglect the mass of the spring)

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a

10 kg

b

0.98 kg

c

5 kg

d

20 kg

answer is B.

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Detailed Solution

Using  F=kx⇒10g=k×0.25⇒k=10g0.25=98×4Now  T=2πmk⇒m=T24π2k⇒m=π2100×14π2×98×4=0.98 kg
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