First slide

Applications of SHM

Question

The scale of a spring balance reading from 0 to 10 kg is 0.25 m long. A body suspended from the balance oscillates vertically with a period of $π / 10$ second. The mass suspended is (neglect the mass of the spring)

Moderate

A

10 kg
B

0.98 kg
C

5 kg
D

20 kg

Solution

Using $F = kx \Rightarrow 10 g = k \times 0 .25 \Rightarrow k = \frac{10 g}{0 .25} = 98 \times 4$
Now $T = 2 π \sqrt{\frac{m}{k}} \Rightarrow m = \frac{T^{2}}{4 π^{2}} k$
$\Rightarrow m = \frac{π^{2}}{100} \times \frac{1}{4 π^{2}} \times 98 \times 4 = 0 .98 kg$

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