Download the app

Questions  

A scooter accelerates from rest for time t1 at constant rate a1 and then retards at constant rate a2 for time t2 and comes to rest. The correct value of t1t2will be :

a
a1a2
b
a2a1
c
a1+a2a1
d
a1+a2a2

detailed solution

Correct option is B

Using,v=u+at Case 1: v=0+a1t1 Case 2:0=v+−a2t Solving, ⇒a1t1=a2t2⇒t1t2=a2a1

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A particle is moving along the x-axis whose acceleration is given by a=3x4, where x is the location of the particle. At t = 0, the particle is at rest at x = 4/3 m. The distance travelled by the particle in 5 s is


phone icon
whats app icon