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Q.

A screen is at a distance of 2 m from narrow slits that are illuminated with light of 589nm. The 10th minimum lies at 0.005 m on either side of the central maximum, then the distance between the slits will be

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a

0.024 mm

b

2.23 mm

c

2.4 mm

d

24 mm

answer is B.

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Detailed Solution

The given values are D=2m, λ=589nm=589×10−9m, n=10thmin, Y=0.005m,  d=? dYD=(2n−1)λ2 d0.0052=(2×10−1)589×10−92 ⇒  d=2.23 mm
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