A screen is placed 50 cm from a single slit, which is illuminated with 6000Å light. If distance between the first and third minima in the diffraction pattern is 3 mm, the width of the slit is (in mm)

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answer is 0000.20.

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Detailed Solution

Position of nth minima yn=nλDd Distance between the first and third minima = (y3−y1)=λDd(3−1)=2λDd ∴3×10−3=2×6000×10−10×0.5d ⇒d=0.2×10−3m=0.2 mm

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