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Q.

A screen is placed 2 m away of a single narrow slit. Calculate the slit width if the first minima lies 5 mm of either side of central maxima if the incident plane wave has a wavelength of 5000 A0

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a

2×10-4m

b

10-5m

c

5×10-5m

d

10-3 m

answer is A.

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Detailed Solution

for the first minima sinθ=λa=xD so a=λ Dxhere D=2m and x = 5 mm λ=5×10-7mthen a=a=5×10-7×25×10-3= 2×10-4m

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