First slide

Measurement

Question

A screw gauge gives the following reading, when used to measure the diameter of a wire.
Main scale reading : 0 mm
Circular scale reading : 52 divisions
Given that 1 mm on main scale corresponds to 100 divisions of the circular scale
The diameter of the wire from the above data is

Moderate

A

0.026 cm
B

0.016 m
C

0.052 cm
D

0.062 m

Solution

Diameter of wire = MSR + CSR $\times$ LC
Given main scale reading (MSR) = 0 mm
Circular scale reading = 52
$L e a s t c o u n t = \frac{V a l u e o f 1 m a i n s c a l e d i v i s i o n}{T o t a l d i v i s i o n s o n c i r c u l a r s c a l e}$
$L C = 0 + 52 \times \frac{1}{100}$
= 0.52 mm
= 0.052 cm

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