A sealed tank containing a liquid of density ρ moves with horizontal acceleration a as shown in the figure. The difference in pressure between two points A and B will be
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a
hρg
b
lρg
c
hρg+lρa
d
hρg−lρa
answer is C.
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Detailed Solution
The points A and C are in same horizontal level hence PC−PA=ρal(refer to figure in question to identify A, B, C) Now, PB−PC=ρgh⇒PB=PA+ρal+ρgh ⇒PB−PA=hρg+lρa