A sealed tank containing a liquid of density ρ moves with a horizontal acceleration a, as shown in the figure. The difference in pressure between the points A and B is

Consider narrow tubes AB and BC each of cross-sectional area ΔS.In Fig-(1): pB.ΔS - pA.ΔS = (ρ.ΔS.l).a ⇒ pB - pA = ρal.....(1)In Fig-(2): pB.ΔS + (ρ.ΔS.h)g = pC.ΔS ⇒ pC - pB = ρgh.....(2)Adding, pC - pA = (ρal + ρgh)