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The seave of a galvanometer of resistance 100 Ω contains 25 division. It gives a deflection of one division on passing a current of 4 x 10-4 a ampere. The resistance in ohm to be added to it, so that it may become a voltmeter of range 2.5 volt is

a
100
b
150
c
250
d
300

detailed solution

Correct option is B

For full scale deflectionig=25×4×10−4=10−2ampNow, R=Vig−G=2⋅510−5−100=150Ω

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