The secondary coil of an ideal step down transformer is delivering 500 watt power at 12.5 A current. If the ratio of turns in the primary to the secondary is 5: 1, then the current flowing in the primary coil will be :

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62.5 A

2.5 A

6 A

0.4 A

answer is B.

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Detailed Solution

P = VIFor secondary:V2 =P2I2=50012.5=40 voltsFor an ideal transformer (100% efficient)Pinput = Poutput ⇒ V1 I1 = V2I2⇒I1=V2I2V1=40(12.5)40 × 5=2.5 A.∵ n1n2 = V1V2 ⇒ 51 = V140

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