The secondary coil of an ideal step down transformer is delivering $$500$$ watt power at $$12.5$$ A current. If the ratio of turns in the primary to the secondary is $$5$$: $$1$$, then the current flowing in the primary coil will be :

Question

Infinity Learn · Accepted Answer

P $$=$$ VIFor secondary:$$V2$$ $$=P2I2=50012.5=40$$ voltsFor an ideal transformer $$(100$$% $$efficient)Pinput$$ $$=$$ Poutput ⇒ $$V1$$ $$I1$$ $$=$$ $$V2I2$$⇒$$I1=V2I2V1=40(12.5)40$$ × $$5=2.5$$ A.∵ $$n1n2$$ $$=$$ $$V1V2$$  ⇒  $$51$$ $$=$$ $$V140$$

The secondary coil of an ideal step down transformer is delivering 500 watt power at 12.5 A current. If the ratio of turns in the primary to the secondary is 5: 1, then the current flowing in the primary coil will be :

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