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Q.

In semiconductor, the concentration of electrons and holes are 8×1018/m3 and 5×1018/m3, respectively. If the mobilities of electrons and hole are 2.3m2/ volt-sec and 0.01m2/volt-sec, respectively, then semiconductor is

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a

N-type and its resistivity is 0.34 ohm-metre

b

P-type and its resistivity is 0.034 ohm-metre

c

N-type and its resistivity is 0.034 ohm-metre

d

P- type and its resistivity is 3.40 ohm-metre

answer is A.

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Detailed Solution

ne=8×1018/m3,nh=5×1018/m3μe=2.3m2volt−sec,μh=0.01m2volt−sec∵ne>nh, so __ semiconductor is N− type.  Also __ conductivity σ=1 Resistivity (ρ)=eneμe+nhμh⇒1ρ=1.6×10−198×1018×2.3+5×1018×0.01⇒ρ=0.34Ω−m
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