In semiconductor the concentrations of electrons and holes are 8 x 1018/m3 and 5 x 1018/m3, respectively. If the mobilities of electrons and holes are 2.3 m2/V-s and 0.01 m2/V-s, respectively, then resistivity of semiconductor is
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a
N-type and its resistivity is 0.34 Ωm
b
P-type and its resistivity is 0.034 Ωm
c
N-type and its resistivity is 0.034 Ωm
d
P-type and its resistivity is 3.40 Ωm
answer is A.
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Detailed Solution
ne=8×1018/m3,nh=5×1018/m3μe=2.3m2V−s,μh=0.01m2V−s∵ne>nh, So semiconductor is N−typeAlso, conductivity, σ=1Resistivityρ=eneμe+nhμh⇒1ρ=1.6×10−198×1018×2.3+5×1018×0.01⇒ρ=0.34 Ω−m