A semiconductor has an electron concentration of $$0.45$$×$$1012$$ m−$$3$$ and a hole concentration of $$5$$×$$1020m$$−$$3$$. Calculate its conductivity. Given electron mobility is $$0.135m2v$$−$$1s$$−$$1$$ . Hole mobility is $$0.048m2v$$−$$1s$$−$$1$$

Question

A semiconductor has an electron concentration of  $$0.45$$×$$1012$$ m−$$3$$ and a hole concentration of  $$5$$×$$1020m$$−$$3$$. Calculate its conductivity. Given electron mobility is $$0.135m2v$$−$$1s$$−$$1$$ . Hole mobility is $$0.048m2v$$−$$1s$$−$$1$$

Infinity Learn · Accepted Answer

Conductivity of semiconductor is the sum of the conductivities due to electrons and holesGiven , $$ne=0.45$$×$$1012m$$−$$3nh=5$$×$$1020m$$−$$3$$μ$$e=0.135m2v$$−$$1s$$−$$1$$μ$$h=0.048m2v$$−$$1s$$−$$1Conductivity$$ , σ$$=$$σ$$e+$$σh ⇒σ$$=nee$$μ$$e+nhe$$μhne<<<

A semiconductor has an electron concentration of $0.45 \times 10^{12} m^{- 3}$ and a hole concentration of $5 \times 10^{20} m^{- 3}$ . Calculate its conductivity. Given electron mobility is $0.135 m^{2} v^{- 1} s^{- 1}$ . Hole mobility is $0.048 m^{2} v^{- 1} s^{- 1}$

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

A semiconductor has an electron concentration of 0.45×1012 m−3 and a hole concentration of 5×1020m−3. Calculate its conductivity. Given electron mobility is 0.135m2v−1s−1 . Hole mobility is 0.048m2v−1s−1

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

A semiconductor has an electron concentration of $0.45 \times 10^{12} m^{- 3}$ and a hole concentration of $5 \times 10^{20} m^{- 3}$ . Calculate its conductivity. Given electron mobility is $0.135 m^{2} v^{- 1} s^{- 1}$ . Hole mobility is $0.048 m^{2} v^{- 1} s^{- 1}$