Questions
A semiconductor P-N junction is to be forward biased with a battery of e.m.f. 1.5 volt. If a potential difference of 0.5 V appears on the junction which does not depend on current. Then to use the junction at 5 mA current, the resistance required to be connected in its series will be
detailed solution
Correct option is D
net potential difference across the resistor is 1.5 - 0.5 = 1 Vaccording to Ohm's law 1=5×10-3RR=1035=200 ΩTalk to our academic expert!
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The diode used in the circuit has barrier voltage 0.5 V and maximum power rating is 10 mW. What should be the minimum value of resistance R connected in series with the diode
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