First slide

P-N junction diode

Question

A semiconductor P-N junction is to be forward biased with a battery of e.m.f. 1.5 volt. If a potential difference of 0.5 V appears on the junction which does not depend on current. Then to use the junction at 5 mA current, the resistance required to be connected in its series will be

Moderate

A

3 kilo ohms
B

300 ohms
C

300 kilo ohms
D

200 ohms

Solution

net potential difference across the resistor is 1.5 - 0.5 = 1 V
according to Ohm's law
$\begin{array}{rcl} 1 & = & 5 \times 10^{- 3} R \\ R & = & \frac{10^{3}}{5} = 200 Ω \end{array}$

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