Q.
A semi-cylinder made of transparent plastic has a refractive index n = 2 and a radius of R. There is a narrow incident light ray perpendicular to the flat side of the semi cylinder at d distance from the axis of symmetry.What can the maximum value of d be so that the light ray can still leave the other side of the semi cylinder?When the value of d chosen is such that TIR just takes place then time for which light remains inside the cylinder is:Distance d is now varied, so that the ray always emerges from the other side of the semi cylinder. What is the range of OB?
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a
d=R2
b
d=R22
c
R2
d
None of these
e
4Rc
f
42Rc
g
22Rc
h
2Rc
i
22R>OB>R2
j
52R>OB>R
k
∞>OB>R2
l
∞>OB>2R2
answer is