Q.

Separation between the plates of a parallel plate capacitor is d and the area of each plate is A. When a slab of material of dielectric constant k and thickness t(t

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a

ε0Ad+t1−1k

b

ε0Ad+t1+1k

c

ε0Ad−t1−1k

d

ε0Ad−t1+1k

answer is C.

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Detailed Solution

Potential difference between the plates V=Vair +Vmedium =σε0×(d−t)+σKε0×t⇒V=σε0d−t+tK=QAε0d−t+tKHence capacitance C=QV=QQAε0(d−t+tK)=ε0A(d−t+tk)=ε0Ad−t 1−1k
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