In a series circuit  C=4μF,    L=2mH and R=20  Ω, when the current in the circuit is maximum, at that time the ratio of the energies stored in the capacitor and the inductor will be

Current will be maximum in the condition of resonance so  imax=ER=E20AEnergy stored in the coil   WL=12Limax2=12LE202=12×2×10−3E2400=14×10−5E2 joule  Energy stored in the capacitor WC=12CE2=12×4×10−6E2=2×10−6E2 joule        Ec/E:L=4:5