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In a series circuit $C = 4 μ F, L = 2 m H$ and $R = 20 Ω,$ when the current in the circuit is maximum, at that time the ratio of the energies stored in the capacitor and the inductor will be

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Correct option is B

Current will be maximum in the condition of resonance so imax=ER=E20AEnergy stored in the coil WL=12Limax2=12LE202=12×2×10−3E2400=14×10−5E2 joule Energy stored in the capacitor WC=12CE2=12×4×10−6E2=2×10−6E2 joule Ec/E:L=4:5

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In a series circuit C=4μF, L=2mH and R=20 Ω, when the current in the circuit is maximum, at that time the ratio of the energies stored in the capacitor and the inductor will be

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Ready to Test Your Skills?

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In a series circuit $C = 4 μ F, L = 2 m H$ and $R = 20 Ω,$ when the current in the circuit is maximum, at that time the ratio of the energies stored in the capacitor and the inductor will be