In a series circuit, C=2 μF, L=1 mH  and  R=10 Ω.  When the current in the circuit is maximum, at that time the ratio of the energies stored in the capacitor and the inductor will be

Current will be maximum in the condition of resonance, so imax=ER=E10 AEnergy stored in the coil, WL=12Limax2=12LE102=12 × 10−3E2100=12 × 10−5 E2  joule Energy stored in the capacitor,WC=12 CE2=12 × 2 × 10−6 E2=10−6E2  joule ∴   WCWL=15