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In a series circuit, $C = 2 μF, L = 1 mH and R = 10 Ω .$ When the current in the circuit is maximum, at that time the ratio of the energies stored in the capacitor and the inductor will be

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Correct option is D

Current will be maximum in the condition of resonance, so imax=ER=E10 AEnergy stored in the coil, WL=12Limax2=12LE102=12 × 10−3E2100=12 × 10−5 E2 joule Energy stored in the capacitor,WC=12 CE2=12 × 2 × 10−6 E2=10−6E2 joule ∴ WCWL=15

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In a series circuit, C=2 μF, L=1 mH and R=10 Ω. When the current in the circuit is maximum, at that time the ratio of the energies stored in the capacitor and the inductor will be

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In a series circuit, $C = 2 μF, L = 1 mH and R = 10 Ω .$ When the current in the circuit is maximum, at that time the ratio of the energies stored in the capacitor and the inductor will be