The series combination of two batteries, both of the same emf 10 V, but different internal resistance of 20Ω and 5Ω , is connected to the parallel combination of two resistors 30Ω and xΩ . The voltage difference across the battery of internal resistance 20Ω is zero, the value of x(in Ω ) is ------
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
answer is 0030.00.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
For first battery, V1=ε1−i.r1 ⇒0=10−i×20 ∵V1=0 ⇒ i=0.5A For second battery , V2=ε2−ir2=10−0.5×5⇒V2=7.5V As per Kirchhoffs rule i=i1+i2 ⇒ 0.5=7.530+7.5x ⇒0.5=0.25+7.5x ⇒7.5x=0.25⇒x=30