Q.

The series combination of two batteries, both of the same emf 10 V, but different internal resistance of 20Ω   and 5Ω  , is connected to the parallel combination of two resistors 30Ω and xΩ . The voltage difference across the battery of internal resistance 20Ω   is zero, the value of x(in Ω ) is ------

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Detailed Solution

For first battery, V1=ε1−i.r1         ​⇒0=10−i×20  ∵V1=0         ​⇒ i=0.5A    For second battery , V2=ε2−ir2=10−0.5×5​⇒V2=7.5V            ​As per Kirchhoffs rule​  i=i1+i2                ​⇒ 0.5=7.530+7.5x    ​⇒0.5=0.25+7.5x ⇒7.5x=0.25​⇒x=30
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