The series combination of two batteries, both of the same emf 10 V, but different internal resistance of 20Ω and 5Ω , is connected to the parallel combination of two resistors 30Ω and xΩ . The voltage difference across the battery of internal resistance 20Ω is zero, the value of x(in Ω ) is ------
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Detailed Solution
For first battery, V1=ε1−i.r1 ⇒0=10−i×20 ∵V1=0 ⇒ i=0.5A For second battery , V2=ε2−ir2=10−0.5×5⇒V2=7.5V As per Kirchhoffs rule i=i1+i2 ⇒ 0.5=7.530+7.5x ⇒0.5=0.25+7.5x ⇒7.5x=0.25⇒x=30