In a series L - C - R circuit frequency of the source is constant and power dissipated in the circuit is maximum when L = 80 mH and C=100 μF. If inductance of the inductor is changed to 100 mH, what will be the capacitance of the capacitor for which the power dissipated in the circuit will be again maximum ?
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a
80 μF
b
120 μF
c
60 μF
d
140 μF
answer is A.
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Detailed Solution
(1)Power dissipated in the circuit is maximum when ωL=1ωCi.e. when ω2 = 1LC∴ 1L'C'=1LC⇒ C'' = LL'.C=80100 × 100 μF=80 μF