In the series L – C – R circuit, the voltage across resistance, capacitance and inductance are 30V each at frequency f = f0 .
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
It the inductor is short-circuited, the voltage across the capacitor will be 302V
b
If the capacitor is short-circuited, the voltage drop across the inductor will be302V
c
If the frequency is changed to 2f0, the ratio of reactance of the inductor to that of the capacitor is 4 : 1.
d
If the frequency is changed to 2f0, the ratio of the reactance of the inductor to that of the capacitor is 1 : 4.
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
VL=VC=VR;⇒XL=XC=Rwhen inductor is short circuitedZ=R2+xc2=2R∴I=30Z=302R∴VL=ixL=302R×R=302∴(A) is incorrect and with similar calculations (B) will be correct. Here f0 is the resonance frequency as vL = vC⇒f0=12πLC and ω0=2πf0=1LCxLxC=ωL1/ωC=ω2LC Given f=2f0⇒ω=2ω0∴xLxC=4∴(C) is also correct.