Electrical Resonance series circuit

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Question

In a series L-C-R circuit $C = 10 μF, R = 10 Ω$ . If the Q-value of the circuit is 10, find ‘L’.

Easy

Solution

$\begin{array}{l} Q = \frac{1}{R} \sqrt{\frac{L}{C}} \\ \Rightarrow L = {CR}^{2} Q^{2} = 10 \times 10^{- 6} \times 10^{2} \times 10^{2} H = 10^{- 1} H = 100 mH \end{array}$

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