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Q.

In the series LCR circuit as shown in figure, the heat developed in 80 seconds and amplitude of wattless current is:

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a

4000 J, 3 A

b

8000 J, 3 A

c

4000 J, 4 A

d

8000 J, 5 A

answer is A.

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Detailed Solution

Heat =irms2⋅Rtirms=i02=25Z2 where, Z=R2+xL−xC2=42+(7−4)2=5Ω⇒ Heat =25522×4×80=4000J and Amplitude of wattless current = i0sin⁡ϕwhere; ϕ=tan−1⁡xL−xCR=tan−1⁡7−44=37∘⇒Amplitude =i0sin⁡37∘=255×35=3 ampere
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