Questions
A series LCR circuit is tuned to resonance. The impedance of the circuit now is
a
[R2+(ωL−1ωC)2]1/2
b
[R2+(ωL+1ωC)2]1/2
c
[R2+(1ωC−ωL)2]1/2
d
R
detailed solution
Correct option is D
Impedance of the LCR circuit is give n b Z=R2+(ωL−1ωc)2 At resonanance impedance of the circuit is minimum and it is equal to resistanceR.∴Z=RTalk to our academic expert!
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In the series LCR circuit as shown in figure, the heat developed in 80 seconds and amplitude of wattless current is:
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