In a series LCR circuit, the voltage across the resistance, capacitance and inductance is 10 V each. If the capacitance is short circuited, the voltage across the inductance will be

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10 V

10/2V

10/3V

20 V

answer is B.

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Detailed Solution

Here R = XL = XC (∴ voltage across them is same) When capacitor is short circuited,I=10R2+XL21/2=102R∴ Potential drop across inductance =IXL=IR=10/2V

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