In a series LCR circuit, the voltage across the resistance, capacitance and inductance is 10 V each. If the capacitance is short circuited, the voltage across the inductance will be

Here R=XL=XC (∵ voltage across them is same)Total voltage in the circuit,V=IR2+XL−XC21/2= IR = 10 voltWhen capacitor is short circuited,I=10R2+XL21/2=102R∴    Potential drop across inductance=LXL=IR=102 volt